If the rate of change of sine of an angle 0 is k, then the rate of change of its tangent is

If the rate of change of sine of an angle $0$ is $k$ , then the rate of change of its tangent is

A
$k^{2}$
B
$\frac{1}{k^{2}}$
C
$k$
D
$\frac{1}{k}$

Solution:

We have,

$\begin{aligned} \frac{d}{d θ} (\sin θ) = k \Rightarrow \cos θ = k \\ ∴ \frac{d}{d θ} (\tan θ) = \sec^{2} θ = \frac{1}{k^{2}} \end{aligned}$

Related content

JEE Main 2023 Question Papers with Solutions

JEE Main 2024 Syllabus

Best Books for JEE Main 2024

JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria

JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria

JEE 2024: Exam Date, Syllabus, Eligibility Criteria

NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3

JEE Crash Course – JEE Crash Course 2023

NEET Crash Course – NEET Crash Course 2023

JEE Advanced Crash Course – JEE Advanced Crash Course 2023