If the roots of the equation x2−2ax+a2+a−3=0 are real and less than 3 then

If the roots of the equation x22ax+a2+a3=0 are real and less than 3 then

  1. A

    a<2

  2. B

    2a3

  3. C

    3<a3

  4. D

    a>4

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    Solution:

    D0124a0

    f(3)>0a25a+6>0

    b2a<3a<3

    Solving a(,2)

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