MathematicsIf the roots of (b−c)x2+(c−a)x+(a−b)=0 are equal, then

If the roots of $(b - c) x^{2} + (c - a) x + (a - b) = 0$ are equal, then

A
$b = a + c$
B
$3 b = a + 2 c$
C
$b = 2 a + 3 c$
D
$2 b = a + c$

Solution:

Roots are equal, then $Δ = 0$

If $a + b + c = 0$ roots are $1, \frac{c}{a}$

$1, \frac{a - b}{b - c}$

$b - c = a - b$

$∴ 2 b = a + c$

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