If the sum of the squares of the distance of a point from the three coordinate axes be 36, then its distance from the origin is

# If the sum of the squares of the distance of a point from the three coordinate axes be 36, then its distance from the origin is

1. A

5

2. B

$3\sqrt{2}$

3. C

$\sqrt{21}$

4. D

$3\sqrt{3}$

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### Solution:

Let P(x, y, z).Now under given condition, we get

Then distance from origin to the point (x, y, z) is

$\sqrt{{\mathrm{x}}^{2}+{\mathrm{y}}^{2}+{\mathrm{z}}^{2}}=\sqrt{18}=3\sqrt{2}$

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