If the sum of the squares of the distance of a point from the three coordinate axes be 36, then its distance from the origin is

If the sum of the squares of the distance of a point from the three coordinate axes be 36, then its distance from the origin is

  1. A

    5

  2. B

    32

  3. C

    21

  4. D

    33

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    Solution:

    Let P(x, y, z).Now under given condition, we get

    x2+y22+y2+z22+z2+x22=36 x2+y2+z2=18

    Then distance from origin to the point (x, y, z) is 

    x2+y2+z2=18=32

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