If the tangent at (1, 7) to the curve, x2=y−6 touches the circle x2+y2+16x+12y+c=0 then the value of c is 

If the tangent at (1, 7) to the curve, x2=y6 touches the circle x2+y2+16x+12y+c=0 then the value of c is 

  1. A

    95

  2. B

    195

  3. C

    185

  4. D

    85

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    Solution:

    The equation of tangent at (1, 7) to x2=y6 is 2xy+5=0 

    The perpendicular distance of Centre (-8, -6) to the line 2xy+5=0 should be equal to the radius of the circle.

     64+36c=|16+6+5|5

     5=100cc=95

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