If the value of limx→0 (1−x)n−1x is 100 , then n=

If the value of limx0(1x)n1x is 100 , then n=

  1. A

    100

  2. B

    -100

  3. C

    99

  4. D

    -99

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    Solution:

    We have, 

    limx0(1x)n1x=100=limx0(1x)n1n(1x)1=100=n(1)n1=100n=100

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