Solution:
Choosing three vertices of a regular hexagon alternately, only two equilateral triangles are possible,
i.e., and Hence,
required probability=
If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is
If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is
