If two dice are thrown simultaneously, then the probability that the sum of the numbers which come up on the dice to be more than 5 is

A
5/36
B
1/6
C
5/18
D
13/18

Solution:

Total number of outcomes in sample space, n(S)=6x6=36
Let E = Event of getting maximum sum of numbers on two dice is 5
= (1, 1), (1, 2), (2, 1), (1,3), (3, 1), (2, 2),(1, 4), (4, 1), (2, 3), (3, 2))
$∴$ n(E) = 10
$∴$ P (the maximum sum of numbers on two dice is 5) $= \frac{n (E)}{n (S)} = \frac{10}{36} = \frac{5}{18}$

$∴$ P (sum of number on two dice i8 more that 5) = 1 - P (the maximum sum on the two die is 5) $= 1 - \frac{5}{18} = \frac{13}{18}$

Solution:

Related content