If two dice are thrown simultaneously, then the probability that the sum of the numbers which come up on the dice to be more than 5 is

If two dice are thrown simultaneously, then the probability that the sum of the numbers which come up on the dice to be more than 5 is

  1. A

    5/36

  2. B

    1/6

  3. C

    5/18

  4. D

    13/18

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    Solution:

    Total number of outcomes in sample space, n(S)=6x6=36
    Let E = Event of getting maximum sum of numbers on two dice is 5
    = (1, 1), (1, 2), (2, 1), (1,3), (3, 1), (2, 2),(1, 4), (4, 1), (2, 3), (3, 2))
     n(E) = 10
     P (the maximum sum of numbers on two dice is 5) =n(E)n(S)=1036=518

    P (sum of number on two dice i8 more that 5) = 1 - P (the maximum sum on the two die is 5)=1518=1318

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