If x3+y3=4, then dydx= - Infinity Learn

$x^{3} + y^{3} = 4$

Differentiate with respect to $' x'$ $o . b . s$

$\frac{d}{d x} (x^{3} + y^{3}) = \frac{d}{d x} (4)$

$3 x^{2} + 3 y^{2} \frac{d y}{d x} = 0$

$3 y^{2} \frac{d y}{d x} = - 3 x^{2}$

$\frac{d y}{d x} = \frac{- 3 x^{2}}{3 y^{2}}$

$\frac{d y}{d x} = \frac{- x^{2}}{y^{2}}$

If $x^{3} + y^{3} = 4$ , then $\frac{d y}{d x} =$