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If  x3+y3=4, then  dydx=

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a
x2y2
b
x2y2
c
y2x2
d
y2x2

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detailed solution

Correct option is B

x3+y3=4

Differentiate with respect to 'x' o.b.s

ddx(x3+y3)=ddx(4)

3x2+3y2dydx=0

3y2dydx=3x2

dydx=3x23y2

dydx=x2y2

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