If 0≤x<π2 ,then the number of values of x for which  sin⁡x−sin⁡2x+sin⁡3x=0 , is 

If 0x<π2 ,then the number of values of x for which  sinxsin2x+sin3x=0 , is 

  1. A

    2

  2. B

    1

  3. C

    3

  4. D

    4

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    Solution:

    we have,

    sinxsin2x+sin3x=0(sin3x+sinx)sin2x=02sin2xcosxsin2x=0sin2x(2cosx1)=0sin2x=0,cosx=12x=0,π3 0x<π2

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