Mathematics If 19-x2=1k13-x+13+x, then k=

 If 19-x2=1k13-x+13+x, then k=

  1. A

    2

  2. B

    4

  3. C

    6

  4. D

    8

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    Solution:

    we have,

    19-x2=1k13-x+13+x

    19-x2=1k3+x+3-x(3-x)(3+x)

    19-x2=1k69-x2

    by canceling 9-x2 from both LHS and RHS

    1=6k

    hence, k=6

    The correct option is C.

     

     

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