If θ∈π2,3π2, then sin-1(sinθ) equals

If θπ2,3π2, then sin-1(sinθ) equals

  1. A

    θ

  2. B

    π-θ

  3. C

    2π-θ

  4. D

    -π+θ

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    Solution:

    We have,

    θπ2,3π2θ3π2,π2πθπ2,π2

    Also, sin(πθ)=sinθ

     sin1(sinθ)=sin1(sin(πθ))=πθ

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