If  2n+1Pn−1:2n−1Pn=3:5 then the value of n is equal to

If  2n+1Pn1:2n1Pn=3:5 then the value of n is equal to

  1. A

    3

  2. B

    4

  3. C

    5

  4. D

    6

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    Solution:

    We have,  2n+1Pn1:2n1Pn=3:5

          2n+1Pn12n1Pn=35    (2n+1)!(n+2)!×(n1)!(2n1)!=35    (2n+1)(2n)(n+2)(n+1)n=35      10(2n+1)=3(n+2)(n+1)    3n211n4=0    (n4)(3n+1)=0n=4

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