If 2sin⁡x−1≤0 and x∈[0,2π]. then the solution set for x, is

If 2sinx10 and x[0,2π]then the solution set for x, is

  1. A

    [π/6,5π/6]

  2. B

    [0,π/6][5π/6,π]

  3. C

    [0,π/6][5π/6,2π]

  4. D

    none of these. 

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    It is  from the graph of y=sinx that

     sinx12 for all x[0,π/6][5π/6,2π]

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.