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If 2w+1=3i, then the determinant Δ=11111w2w21w2w4 is 

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a
3w
b
3w(w – 1)
c
3w2
d
3w(1 – w)

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detailed solution

Correct option is B

w=12+i32,w3=1, and Δ=3w3w2

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