If 4Cos2θ=3 then Î¸=−−−−

If 4Cos2θ=3 then Î¸=−−−−

  1. A

    π6,5π6

  2. B

    π4,3π4

  3. C

    π3,2π3

  4. D

    ±π2

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    Solution:

    4cos2θ=3

    ⇒cos2θ=322⇒θ=nπ±π6

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