If A=[24−65 ] and B=[4−357], then 3A+2B=

A
$[\begin{matrix} 6 & 12 \\ - 18 & 15 \end{matrix}]$
B
$[\begin{matrix} 14 & 6 \\ - 8 & 29 \end{matrix}]$
C
$[\begin{matrix} 8 & - 6 \\ 10 & 14 \end{matrix}]$
D
$[\begin{matrix} 14 & 6 \\ - 28 & 29 \end{matrix}]$

Solution:

$\begin{array}{l} 3 A + 2 B = 3 [\begin{matrix} 2 & 4 \\ - 6 & 5 \end{matrix}] + 2 [\begin{matrix} 4 & - 3 \\ 5 & 7 \end{matrix}] = [\begin{matrix} 6 & 12 \\ - 18 & 15 \end{matrix}] + [\begin{matrix} 8 & - 6 \\ 10 & 14 \end{matrix}] \\ = [\begin{matrix} 6 + 8 & 12 - 6 \\ - 18 + 10 & 15 + 14 \end{matrix}] = [\begin{matrix} 14 & 6 \\ - 8 & 29 \end{matrix}] \end{array}$

If $A = [\begin{matrix} 2 & 4 \\ - 6 & 5 \end{matrix}] a n d B = [\begin{matrix} 4 & - 3 \\ 5 & 7 \end{matrix}]$ , then $3 A + 2 B =$

Solution:

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