If a is a real number and if the middle term of a3+38 is 1120, then value of a is

If a is a real number and if the middle term of a3+38 is 1120, then value of a is

  1. A

    ±2

  2. B

    ±1

  3. C

    ±3

  4. D

    ±2

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    Solution:

    Middle term of a3+38 is the 82+1 th or 5th term. We have

    T5=T4+1=8C4a34(3)4=70a4

    We are given T5=112070a4=1120

     a4=16=24a=±2

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