if a is a repeated root of  ax2+bx+c=0, limx→αsin⁡ax2+bx+c(x−α)2 is equal to 

if a is a repeated root of  ax2+bx+c=0limxαsinax2+bx+c(xα)2 is equal to 

  1. A

    0

  2. B

    a

  3. C

    b

  4. D

    e

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    Solution:

    Since  a is a repeated root of ax2+bx+c=0

     ax2+bx+c=a(xα)2

    limxαsinax2+bx+c(xα)2=limxαsina(xα)2(xα)2=alimxαsina(xα)2a(xα)2=a×1=a.

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