If f:{1,2,3,…..}→{0,±1,±2,….} is defined by f(n)=n/2               if n is even −n−12     if n is odd then f−1(−100) is 

If f:{1,2,3,..}{0,±1,±2,.} is defined by f(n)=n/2               if n is even n12     if n is odd then f1(100) is 

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    Solution:

    Let f1(100)=xf(x)=100
    (x1)2=100x=201

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