MathematicsIf f(1)=3, f'(1)=2,then ddx{logf(ex+2x)} at x=0 is _____________

If f(1)=3, f'(1)=2,then ddx{logf(ex+2x)} at x=0 is _____________

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    Solution:

    Let y=ddx{logf(ex+2x)}=f(ex+2x)(ex+2)f(ex+2x)

    (y)x=0=1f(1)f(1)3=233=2.

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