If f:R→R, g :R→R be two functions given by f(x)=2x-3, g(x)=x3+5. Then,fog-1(x) is equal to 

If f:RR, g :RR be two functions given by f(x)=2x-3, g(x)=x3+5. Then,fog-1(x) is equal to 

  1. A

    x+721/3

  2. B

    x-721/3

  3. C

    x-271/3

  4. D

    x-721/3

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    Solution:

    f:RR g:RR f(x)=2x-3 g(x)=x3+5         (fog)(x)=f(g(x))=f(x3+5)=2(x3+5)-3                            =2x3+7
    Now,     let let     y=2x3+7         2x3=y-7           x=y-721/3       
    Replacing  x by y, we get
                   y=x-721/3         (fog)-1(x)=x-721/3

     

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