Search for: If f:R→R, g :R→R be two functions given by f(x)=2x-3, g(x)=x3+5. Then,fog-1(x) is equal to If f:R→R, g :R→R be two functions given by f(x)=2x-3, g(x)=x3+5. Then,fog-1(x) is equal to Ax+721/3Bx-721/3Cx-271/3Dx-721/3 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:f:R→R g:R→R f(x)=2x-3 g(x)=x3+5 ⇒ (fog)(x)=f(g(x))=f(x3+5)=2(x3+5)-3 =2x3+7Now, let let y=2x3+7 2x3=y-7 x=y-721/3 Replacing x by y, we get y=x-721/3 ∴ (fog)-1(x)=x-721/3 Related content Oppositional Defiant Disorders Good Friday Wishes CBSE Class 9 Physics Motion Worksheet Autism Spectrum Disorder Sine and Cosine Waves Hindu Festivals List 2024 JEE Main Eligibility Criteria 2024 Session 2 (Released), Age Limits, Qualifying Marks, and Important Factor MCQs on Plant Hormones Class 10 5 Reasons To Choose The Commerce Stream After 10th Fl Words