If f(x)=loge⁡1−x1+x,|x|<1 then f2x1+x2 is equal to,

If f(x)=loge1x1+x,|x|<1 then f2x1+x2 is equal to,

  1. A

    2fx2

  2. B

    2f(x)

  3. C

    (f(x))2

  4. D

    2f(x)

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    Solution:

    Here f(x)=loge1x1+x

    Now, f2x1+x2=loge12x1+x21+2x1+x2

    loge1+x22x1+x2+2x=loge1x1+x2=2loge1x1+x=2f(x)

     

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