If f(x)=xsin⁡1x,    x≠00,    x=0 Then limx→0 f(x)

# If $f\left(x\right)=\left\{\begin{array}{l}x\mathrm{sin}\left(\frac{1}{x}\right), x\ne 0\\ 0, x=0\end{array}\right\$ Then $\underset{x\to 0}{lim} f\left(x\right)$

1. A

1

2. B

-1

3. C

0

4. D

does not exist

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### Solution:

We have,

Similarly, we obtain

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