If I1=∫01 1−x50100dx,I2=∫01 1−x50101 and I2=αI1, then α equals to 

If I1=011x50100dx,I2=011x50101 and I2=αI1, then α equals to 

  1. A

    50495050

  2. B

    50515050

  3. C

    50505051

  4. D

    50505049

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    Solution:

    We have, 

    i1=011x50100dx and I2=011x50101dx

    Now,

    ∴=011x50101dx

    I2=011x501001x50dx

    I2=011x50100dx01x501x50100dx

        I2=I1+150011x5010050x49dx    I2=I1+15001x1x50100ddx1x50dx    I2=I1+150x1x5010110101011x50101101dx    I2=I115050I2    50515050I2=I1I2I1=50505051.

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