If I=∫x276x2+5x+4×2+x+16dx=f(x)+C, then f(x) is equal to

If I=x276x2+5x+4x2+x+16dx=f(x)+C, then f(x) is equal to

  1. A

    17x6+x5+x47

  2. B

    176x5+5x4+4x37

  3. C

    176x6+5x5+4x47

  4. D

    17x5+x4+x37

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    Solution:

    We have

    I=x276x2+5x+4x2+x+16dx  I=6x5+5x4+4x3x6+x5+x46dx I=x6+x5+x46dx6+x5+x4=17x6+x5+x4+C

    Hence, f(x)=17x6+x5+x47.

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