If P={θ:sin⁡θ−cos⁡θ=2cos⁡θ}  and Q={θ:sin⁡θ+cos⁡θ=2sin⁡θ} are two sets. Then, 

If P={θ:sinθcosθ=2cosθ}  and Q={θ:sinθ+cosθ=2sinθ} are two sets. Then, 

  1. A

    PQ and QPϕ

  2. B

    QP

  3. C

    PQ

  4. D

    P=Q

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    Solution:

    cosθ(2+1)=sinθtanθ=2+1 and sinθ(21)=cosθ

    tanθ=121×2+12+1=(2+1) P=Q

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