If sec⁡x+sec2⁡x=1 then the value of tan8⁡x−tan4⁡x− 2tan2⁡x+1 will be equal to

If secx+sec2x=1 then the value of tan8xtan4x 2tan2x+1 will be equal to

  1. A

    0

  2. B

    1

  3. C

    2

  4. D

    3

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    Solution:

    secx=1sec2x secx=tan2x

    Squaring both side, we get

    sec2x=tan4x 1+tan2x=tan4x

    Squaring both side, we get

    tan8x=tan4x+2tan2x+1 tan8xtan4x2tan2x=1tan8xtan4x2tan2x+1=2

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