If sec⁡x+sec2⁡x=1 then the value of tan8⁡x−tan4⁡x− 2tan2⁡x+1 will be equal to

# If $\mathrm{sec}\mathrm{x}+{\mathrm{sec}}^{2}\mathrm{x}=1$ then the value of will be equal to

1. A

0

2. B

1

3. C

2

4. D

3

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### Solution:

Squaring both side, we get

Squaring both side, we get

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