If sin⁡θ1sin⁡θ2−cos⁡θ1cos⁡θ2+1=0then the value of tan⁡θ1/2cot⁡θ2/2is equal to ______

If sinθ1sinθ2cosθ1cosθ2+1=0then the value of tanθ1/2cotθ2/2is equal to ______

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    Solution:

    sinθ1sinθ2cosθ1cosθ2=1 or cosθ1+θ2=1θ1+θ2=2,nI or θ12+θ22= Thus, tanθ12cotθ22=tanθ12cotθ12=tanθ12cotθ12=1

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