If T=2πlg, then relative errors in T and I are in the ratio 

If T=2πlg, then relative errors in T and I are in the ratio 

  1. A

    1/2

  2. B

    2

  3. C

    1/2π

  4. D

    none of these

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    Solution:

    We have,

    T=2πlg logT=log2π+12logl12log8 1TdT=0+12ldl0 dTT=12dll ΔTT=12Δll                                                          [dTΔT and dlΔl] ΔTTΔll=12 l

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