If x=3+313+323, then x3−9×2+18x−12= 

If x=3+313+323, then x39x2+18x12= 

  1. A

    1

  2. B

    2

  3. C

    3

  4. D

    0

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    Solution:

    x=3+313+323

    x3=313+323       [(a+b)3=a3+b3+3ab(a+b)]

    Cubing  on both sides

    (x3)3=(313+323)3

    x3279x2+27x=3+32+9(x3)    (x3=313+323)

    x39x2+18x12=0

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