If ∫x71+x42dx=14log⁡1+x4+f(x)+C then 

If x71+x42dx=14log1+x4+f(x)+C then 

  1. A

    f(x)=1+x4

  2. B

    f(x)=11+x42

  3. C

    f(x)=11+x4

  4. D

    f(x)=tan11+x4

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    Solution:

    Put  1+x4=t , so that 

    x71+x42dx=14(t1)t2dt=14log|t|+141t+C=14log1+x4+11+x4+Cf(x)=11+x4

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