If x=ycos⁡2π3=zcos⁡4π3, then xy + yz + zx = 

If x=ycos2π3=zcos4π3, then xy + yz + zx = 

  1. A
  2. B
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    Solution:

    We have,

    x=ycos2π3=zcos4π3x=y2=z2x1=y2=z2=λ (say) x=λ,y=2λ,z=2λxy+yz+zx=2λ2+4λ22λ2=0

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