If y=1x then dy1+y4+dx1+x4=

Solution:

$y = \frac{1}{x} \Rightarrow \frac{d y}{d x} = \frac{- 1}{x^{2}} \Rightarrow d y = \frac{- d x}{x^{2}} n o w t h e g i v e n e q u a t i o n = \frac{d y}{\sqrt{1 + y^{4}}} + \frac{d x}{\sqrt{1 + x^{4}}} = \frac{\frac{- d x}{x^{2}}}{\sqrt{1 + \frac{1}{x^{4}}}} + \frac{d x}{\sqrt{1 + x^{4}}} = \frac{\frac{- d x}{x^{2}}}{\frac{\sqrt{1 + x^{4}}}{x^{2}}} + \frac{d x}{\sqrt{1 + x^{4}}} = 0$

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