MathematicsIf y=(2×3−3)(4−x), then dydx=

If $y = (2 x^{3} - 3) (4 - x)$ , then $\frac{d y}{d x} =$

A
$(4 x - 1) (- 3)$
B
$(4 x - 3) (4 - x)$
C
$- 6 x^{2} - 16 x - 3$
D
$- 6 x^{2} + 16 x + 3$

Solution:

$y = (2 x^{2} - 3) (4 - x) = 8 x^{2} - 2 x^{3} - 12 + 3 x$

$\frac{d y}{d x} = 16 x - 6 x^{2} + 3 = - 6 x^{2} + 16 x + 3$

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