If y=tan−1⁡acos⁡x−bsin⁡xbcos⁡x+asin⁡x where −π2<x<π2 and abtan⁡x>−1 then⁡−dydx2=

MathematicsIf y=tan−1⁡acos⁡x−bsin⁡xbcos⁡x+asin⁡x where −π2−1 then⁡−dydx2=

If $y = \tan^{- 1} (\frac{a \cos x - b \sin x}{b \cos x + a \sin x})$ where $- \frac{π}{2} < x < \frac{π}{2} and \frac{a}{b} \tan x > - 1$ $then \frac{(\frac{- d y}{d x})}{2} =$

$y = \tan^{- 1} (\frac{\frac{a}{b} - \tan x}{1 + \frac{a}{b} \tan x}) = \tan^{- 1} (\frac{a}{b}) - \tan^{- 1} (\tan x)$

$\Rightarrow \frac{d y}{d x} = 0 - 1 = - 1$

Area of Square

Pythagoras Theorem

Triangle Formulae

Area Formulae

Volume of Cone Formula