In a class, there are 10 boys and 8 girls. When 3 students are selected at random, the probability that 2 girls and 1 boy are selected, is

In a class, there are 10 boys and 8 girls. When 3 students are selected at random, the probability that 2 girls and 1 boy are selected, is

  1. A

    35102

  2. B

    15102

  3. C

    55102

  4. D

    25102

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    Solution:

    Total number of boys = 10
    Total number of girls = 8
    Number of Students have to be selected at random = 3
    if 2 girls and 1 boy are selected, then the required probability 

    = 8C2×10C1 18C3=8×72×1018×17×163×2nCr=n!r!(nr)!=4×7×10×618×17×16=703×17×4=356×17=35102

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