In a lottery there were 90 tickets numbered 1 to 90. Five tickets were drawn at random- The probability that two of the tickets drawn numbers 15 and 89, is

In a lottery there were 90 tickets numbered 1 to 90. Five tickets were drawn at random- The probability that two of the tickets drawn numbers 15 and 89, is

  1. A

    2/801

  2. B

    2/623

  3. C

    1/267

  4. D

    1/623

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    Solution:

    Out of 90 tickets, two tickets already considered,
    instead of selecting 5 tickets we have to select only 3
    tickets out of 88 tickets.

    Required probability 

    = 88C3 90C5=88×87×863×2×190×89×88×87×865×4×3×2×1=5×490×89=2801 

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