In a ∆ABC , bcos2⁡C2+ccos2⁡B2 is equal to 

In a ABC bcos2C2+ccos2B2 is equal to 

  1. A

    s

  2. B

    2s

  3. C

    s/2

  4. D

    none of these  

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    Solution:

    we have ,

    bcos2C2+ccos2B2=b2(1+cosC)+c2(1+cosB)=12(b+c+bcosC+ccosB)=12(b+c+a)=s

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