In the expansion of (x + a)n , if the sum of odd terms be A and the sum of even terms be B, then value of (x2 – a2 )n is

In the expansion of (x + a)n , if the sum of odd terms be A and the sum of even terms be B, then value of (x2  a2 )n is

  1. A

    AB 

  2. B

    2AB 

  3. C

    4AB 

  4. D

    A2B2

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    Solution:

    We have (x+a)n=A+B and (xa)n=AB 

    x2a2n=(x+a)n(xa)n=(A+B)(AB)=A2B2.

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