It is given that the events A and B are such that P(A)=14, P(A/B)=12 and P(B/A)=23. Then, P(B) is

It is given that the events A and B are such that P(A)=14, P(A/B)=12 and P(B/A)=23. Then, P(B) is

  1. A

    23

  2. B

    12

  3. C

    16

  4. D

    13

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    Solution:

    We have,

                 P(AB)=P(A)P(B/A) P(AB)=14×23=16

    Now, P(A/B)=P(AB)P(B)12=16×1P(B)P(B)=13

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