Search for: Let a1,a2,a3,…………….a49be in A.P. such that∑k=012 a4k+1=416 and a9+a43′=66 ,a12+a22+…………+a172=140m then m is equal to Let a1,a2,a3,…………….a49be in A.P. such that∑k=012 a4k+1=416 and a9+a43′=66 ,a12+a22+………...+a172=140m then m is equal to A33B66C68D34 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:∑k=012 a4k+1=416⇒a1+a5+…+a49=416 ⇒132a1+a49=416As a49=a1+48d so we have1322a1+48d=416⇒a1+24d=32 …………………... (i) Given, a9+a43=66⇒a1+8d+a1+42d=66⇒a1+25d=33 …………………………….…(ii)The equation (i) and (ii) gives a1=8,d=1Now, a12+a22+…..+a172=82+92+….+242=12+22+…..+242−12+22+….+72=24⋅25⋅496−7⋅8⋅156=4760=34(140)∴ m=34Post navigationPrevious: For any two sets A and B, if A∩X=B∩X=ϕ and A∪X=B∪X for some set X, thenNext: If aN={an:n∈N} and bN∩cN=dN where a,b,c∈N and, b,c are coprime, thenRelated content JEE Main 2023 Result: Session 1 NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria