Let A={ϕ,{ϕ},{ϕ,{ϕ}}}, where ϕis a null set, then

Let $A = {ϕ, {ϕ}, {ϕ, {ϕ}}},$ where $ϕ$ is a null set, then

A
$ϕ \subseteq A, ϕ \in A, {ϕ} \in A, {ϕ} \subseteq A$
B
$ϕ \in A but ϕ \notin A$
C
${ϕ} \in A but {ϕ} \notin A$
D
$A$ is a null set.

Solution:

$ϕ$ is a subset of every set therefore $ϕ \subseteq A$

$ϕ \in A, {ϕ} \in A and {ϕ} \subseteq A$ , because $ϕ \in A$ .

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