Let A  ={  x  :  x   is a multiple of 3 } and B={x:x is a multiple of 5}. Then  A∩B is given by

# Let is a multiple of 3 } and $B=\left\{x:x$ is a multiple of 5}. Then  $A\cap B$ is given by

1. A

$\left\{3,6,9,\dots \right\}$

2. B

$\left\{5,10,15,20,\dots \right\}$

3. C

$\left\{15,30,45,\dots \right\}$

4. D

None of these

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### Solution:

$A\cap B$ will be a set containing multiples of 15.

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