Let A  ={  x  :  x   is a multiple of 3 } and B={x:x is a multiple of 5}. Then  A∩B is given by 

Let A  ={  x  :  x   is a multiple of 3 } and B={x:x is a multiple of 5}. Then  AB is given by

 

  1. A

    {3,6,9,}

  2. B

    {5,10,15,20,}

  3. C

    {15,30,45,}

  4. D

    None of these

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    Solution:

    AB will be a set containing multiples of 15.

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