Let A=x,y,z, B=u,v,w and f:A→B be defined by f(x)=u, f(y)=v, f(z) = w. Then f is 

Let A=x,y,z, B=u,v,w and f:AB be defined by f(x)=u, f(y)=v, f(z) = w. Then f is 

  1. A

    surjective but not injective

  2. B

    injective but not surjective

  3. C

    bijective 

  4. D

    None of the above

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    Solution:

    A={x,y,x}, B={u,v,w} Now, f :AB

    f is one -one and f is onto.

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