Let f(2)=4 and f′(2)=4 Then, limx→2 xf(2)−2f(x)x−2 is given by

Let f(2)=4 and f(2)=4 Then, limx2xf(2)2f(x)x2 is given by

  1. A

    2

  2. B

    -2

  3. C

    -4

  4. D

    3

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    Solution:

    We have, 

        lim      x2xf(2)2f(x)x2=limx2xf(2)2f(2)+2f(2)2f(x)x2=limx2(x2)f(2)x22limx2f(x)f(2)x2=f(2)2f(2)=42×4=4

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