Let I1=∫01 ex1+xdx and I2=∫01 x2ex32−x3dx. Then, I1l2, is equal to

Let I1=01ex1+xdx and I2=01x2ex32x3dxThen, I1l2, is equal to

  1. A

    3e

  2. B

    e3

  3. C

    3e

  4. D

    13e

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    Solution:

    We have,

    I1=01ex1+xdx and I2=01x2ex32x3dx

     l2=13011ex32x33x2dx

     I2=1311et(2t)dt, where t=x3

     I2=13011e1t(1+t)dt 0af(x)dx=0af(ax)

     I2=13e01et1+tdtI2=13eI1I1I2=3e

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