Search for: Let J=∫−5−4 3−x2tan3−x2dx andK=∫−2−1 6−6x+x2tan6x−x2−6dx. Then (J+K) equals __. Let J=∫−5−4 3−x2tan3−x2dx andK=∫−2−1 6−6x+x2tan6x−x2−6dx. Then (J+K) equals __. Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have J=∫−5−4 3−x2tan3−x2dxPut (x+5)=t. ThenJ=∫01 3−(t−5)2tan3−(t−5)2dt=∫01 −22+10t−t2tan−22+10t−t2dtNow K=∫−2−1 6−6x+x2tan6x−x2−6dx.Put (x+2)=z. ThenK=∫01 6−6(z−2)+(z−2)2tan6(z−2)−(z−2)2−6dz=∫01 22−10z+z2tan−22+10z−z2dzHence, (J+K)=0 Related content Oppositional Defiant Disorders Good Friday Wishes CBSE Class 9 Physics Motion Worksheet Autism Spectrum Disorder Sine and Cosine Waves Hindu Festivals List 2024 JEE Main Eligibility Criteria 2024 Session 2 (Released), Age Limits, Qualifying Marks, and Important Factor MCQs on Plant Hormones Class 10 5 Reasons To Choose The Commerce Stream After 10th Fl Words