Let P=limx→0+ 1+tan2⁡x2x. Then loge P, is equal to

Let P=limx0+1+tan2x2x. Then loge P, is equal to

  1. A

    1

  2. B

    12

  3. C

    14

  4. D

    2

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    Solution:

    We have,

    P=limx0+1+tan2x2xP=elimx0+2x1lan2x=e2limx0+tanxx2logeP=12

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