Let X and Y be two events such that P(X)=13, P(X/Y)=12 and P(Y/X)=25. Then,

Let X and Y be two events such that P(X)=13, P(X/Y)=12 and P(Y/X)=25. Then,

  1. A

    PY=715

  2. B

    P(XY)=15  P(XY)=26

  3. C

    P(XY)=25

  4. D

    P(Y)=415 

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    Solution:

    We have,

      P(Y/X)=25P(XY)P(X)=25P(XY)=25P(X)=25×13=215

    It is given that

    P(X/Y)=12P(XY)P(Y)=12P(Y)=2P(XY)=2×215=415

    So, option (d) is correct. 

    Thus, we have

          P(X)=13, P(Y)=415 and P(XY)=215

     P(XY)=P(X)+P(Y)P(XY)=13+415215=715

    So, 

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